Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation set the denominator equal to zero. solve : x - 3 = 0 → x = 3 is the asymptote …

The horizontal asymptote is y = y = (-2/3)x Vertical asymptote (s) To find any vertical asymptotes, factor the numerator and the denominator. Any factor in the denominator containing an x that …

The vertical asymptote is x=-7/3 The oblique asymptote is y=7x There is no horizontal asymptote As you cannot divide by 0, so x=-7/3 is a vertical asymptote. As the degree of the numerator > …

The vertical asymptote is x=2 The oblique asymptote is y=x+2 No horizontal asymptote The domain of f (x) is D_f (x)=RR- {2} As we cannot divide by 0, x!=2 Therefore, The vertical …

Vertical asymptotes are x=sqrt5 and x=-sqrt5 and horizontal asymptote is y=1/2 Vertical asymptotes are given by putting denominator as 0 i.e. 2x^2-10=0 or x^2-5=0 i.e. x=sqrt5 and …

Horizontal asymptote is y=1 A vertical asymptote means when as y->+-oo, x tends to some finite number. This is simpler as we know that such a limit is brought out by the denominator, here x-1.

The vertical asymptote is x=-1/4 The horizontal asymptote is y=-5/4 There are no oblique asymptotes As we cannot divide by 0, the vertical asymptote is x=-1/4 There are no oblique …

Asymptote is at x=-2 If we are given (2x-4)/(x^2-4). The first step for finding the asymptote is to factor EVERYTHING. Let's start with 2x-4. We can easily factor out a 2, leaving the expression …

The vertical asymptote is x=4 The oblique asymptote is y=x+4 No horizontal asymptote. The domain of f (x) is D_f (x)=RR- {4} As you cannot divide by 0, x!=4 The vertical asymptote is …

Vertical asymptotes are x=-1/2 and x=-4 and horizontal asymptote y=3/2 In (3x^2-3x-36)/ (2x^2+9x+4), we get vertical asymptotes by putting denominator as zero i.e. they are given by …